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>java实现URL带参数请求(get/post) 创建者：webmaster 更新时间：2005-05-16 21:01
param 为aaa=111&bbb=222.....格式
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public static String sendGet(String url,String param)
{
String result = "";
try{
String urlName = url + "?"+param;//
URL U = new URL(urlName);
URLConnection connection = U.openConnection();
connection.connect();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
while ((line = in.readLine())!= null)
{
result += line;
}
in.close();
}catch(Exception e){
System.out.println("没有结果！"+e);
}
return result;
}
public static String sendPost(String url,String param)
{
String result="";
try{
URL httpurl = new URL(url);
HttpURLConnection httpConn = (HttpURLConnection)httpurl.openConnection();
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
PrintWriter out = new PrintWriter(httpConn.getOutputStream());
out.print(param);
out.flush();
out.close();
BufferedReader in = new BufferedReader(new InputStreamReader(httpConn.getInputStream()));
String line;
while ((line = in.readLine())!= null)
{
result += line;
}
in.close();
}catch(Exception e){
System.out.println("没有结果！"+e);
}
return result;
}相关文章- 前一则: java锁住一个文件（独占方式访问）
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